为什么1 in [1,0] == True执行结果是False

今天爱分享给大家带来为什么1 in [1,0] == True执行结果是False，希望能够帮助到大家。
有如下

>>> 1 in [1,0]             # This is expected
True
>>> 1 in [1,0] == True     # This is strange
False
>>> (1 in [1,0]) == True   # This is what I wanted it to be
True
>>> 1 in ([1,0] == True)   # But it's not just a precedence issue!
                           # It did not raise an exception on the second example.

Traceback (most recent call last):
  File "", line 1, in 
      1 in ([1,0] == True)
      TypeError: argument of type 'bool' is not iterable

这里python使用了比较运算符链

1 in [1,0] == True

将被转为

(1 in [1, 0]) and ([1, 0] == True)

很显然是false的

同样的

a < b < c

会被转为

(a < b) and (b < c) # b不会被解析两次